t=-16t^2+60t+25

Solution for t=-16t^2+60t+25 equation:

t=-16t^2+60t+25

We move all terms to the left:

t-(-16t^2+60t+25)=0

We get rid of parentheses

16t^2-60t+t-25=0

We add all the numbers together, and all the variables

16t^2-59t-25=0

a = 16; b = -59; c = -25;
Δ = b2-4ac
Δ = -592-4·16·(-25)
Δ = 5081
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-\sqrt{5081}}{2*16}=\frac{59-\sqrt{5081}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+\sqrt{5081}}{2*16}=\frac{59+\sqrt{5081}}{32}
$